18w=90w^2

Solution for 18w=90w^2 equation:

18w=90w^2

We move all terms to the left:

18w-(90w^2)=0

determiningTheFunctionDomain
-90w^2+18w=0

a = -90; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-90)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-90}=\frac{-36}{-180}
=1/5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-90}=\frac{0}{-180}
=0
$